Improve subprocess handler

- Will now output the subprocess console when in dev mode

client/modules/subprocessHandler.mjs

@@ -1,4 +1,6 @@
 import { spawn } from "child_process";
+import dotenv from 'dotenv';
+dotenv.config()
 
 /**
  * Object to store references to spawned processes.
@@ -25,11 +27,29 @@ export const launchProcess = (processName, args, waitForClose=false, pcwd=undefi
         // Store reference to the spawned process
         runningProcesses[processName] = childProcess;
 
+        // Output the process output in development
+        var scriptOutput = "";
+
+        // Get the stdout from the child process
+        childProcess.stdout.setEncoding('utf8');
+        childProcess.stdout.on('data', (data) => {
+            if (process.env.NODE_ENV === "development") console.log(`Data from ${processName}:`, data);
+            scriptOutput += data.toString();
+        });
+
+        // Get the stderr from the child process
+        childProcess.stderr.setEncoding('utf8');
+        childProcess.stderr.on('data', (data) => {
+            if (process.env.NODE_ENV === "development") console.log(`Data from ${processName}:`, data);
+            scriptOutput += data.toString();
+        })
+
         let code = new Promise(res => {
             childProcess.on('exit', (code, signal) => {
                 // Remove reference to the process when it exits
                 delete runningProcesses[processName];
                 console.log(`${processName} process exited with code ${code} and signal ${signal}`);
+                console.log("Child process console output: ", scriptOutput);
                 res(code);
             })
         });